y^2+3-(y+1)(y+2)=0

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Solution for y^2+3-(y+1)(y+2)=0 equation:


Simplifying
y2 + 3 + -1(y + 1)(y + 2) = 0

Reorder the terms:
y2 + 3 + -1(1 + y)(y + 2) = 0

Reorder the terms:
y2 + 3 + -1(1 + y)(2 + y) = 0

Multiply (1 + y) * (2 + y)
y2 + 3 + -1(1(2 + y) + y(2 + y)) = 0
y2 + 3 + -1((2 * 1 + y * 1) + y(2 + y)) = 0
y2 + 3 + -1((2 + 1y) + y(2 + y)) = 0
y2 + 3 + -1(2 + 1y + (2 * y + y * y)) = 0
y2 + 3 + -1(2 + 1y + (2y + y2)) = 0

Combine like terms: 1y + 2y = 3y
y2 + 3 + -1(2 + 3y + y2) = 0
y2 + 3 + (2 * -1 + 3y * -1 + y2 * -1) = 0
y2 + 3 + (-2 + -3y + -1y2) = 0

Reorder the terms:
3 + -2 + -3y + y2 + -1y2 = 0

Combine like terms: 3 + -2 = 1
1 + -3y + y2 + -1y2 = 0

Combine like terms: y2 + -1y2 = 0
1 + -3y + 0 = 0
1 + -3y = 0

Solving
1 + -3y = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -3y = 0 + -1
-3y = 0 + -1

Combine like terms: 0 + -1 = -1
-3y = -1

Divide each side by '-3'.
y = 0.3333333333

Simplifying
y = 0.3333333333

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